Problem p29522
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Technical Merit
To Play
Artistic Impression
Star Rating3.0

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Star Ratings
2007-01-16 07:43:26Markusgoth2122
2007-08-02 17:00:45tomohawk1818
2009-07-06 14:59:09HateYou1627
2011-05-13 12:12:39HarryPotter981861
2011-12-08 18:14:42SirRick1703
2011-12-15 17:21:52Garryback1679
2012-07-12 08:18:2610101615
2013-03-08 17:50:48luffyanderssen1619
2017-08-07 14:23:43floreatdunum1709
2017-08-07 19:16:02chessisajedrez1746

2007-01-16 07:43:26Markusgoth2122Tactical enpassant. 
2009-01-29 17:29:57UriBlass188831.0 seconds Qc3 took time to find 
2009-07-06 14:59:09HateYou1627abcdefghijklmnopqrstuvwxyz 
2010-05-12 16:47:24barz1628r2qr1k1/1p2p3/p5NB/1b1P1p2/6P1/6Q1/P5PP/ 5R1K b - - 0 1 
2011-05-13 12:12:39HarryPotter9818614.9 seconds 
2011-06-17 10:22:16BabyTiger18790.8 seconds 
2011-12-08 18:14:42SirRick1703Qc3 threats so much at the same time (new rating record 1728.43)3,5 s 
2013-03-08 17:50:42luffyanderssen1619well, Qxf4 gives white +21 points according to Fritz, as opposed to the mate in 4 for Qc3 so I'm not so sure that I like this one THAT much. 
2017-08-07 14:42:10floreatdunum1709This problem is a great example of how poorly thought out, some of the CTS problem set is, and I deliberately give it one star. As luffyanderssen points out 2. Qxf4 is also correct. 
2017-08-07 14:44:19floreatdunum1709I set Stockfish on this, fast i7, 24GB RAM. Immediately it leaps to +95 pawns for 2. Qxf4, before qucikly thereafter coming to a stable verdict of mate in 11. Examining the moves of that mate in 11, all black does is throw away all his pieces in a despera 
2017-08-07 14:45:54floreatdunum1709Crap problem. Event 2. Qh4 is a viable solution, which Stockfish initially assigns +4.95, before leaping to +15 fairly quickly, before I got bored of the exercise of working out exactly how rubbish this junk is. 
2017-08-07 14:46:38floreatdunum1709Examining the moves of that mate in 11, all black does is throw away all his pieces in a desperate attempt to stave off the inevitable mate. 
2017-08-08 18:41:05chessisajedrez1746As a lesson, I like the solution because it stresses the importance of the diagonal. As a problem, @floreatdunum makes a strong argument for a dual. 

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Crafty 19.19 3GHZ 5sec

1. ... f4
2. Qc3
({7:Mat04} 2. Qc3 e5 3. dxe6 Qd4 4. Qxd4 Bxf1 5. Qg7# $18)
({7:+0.07} 2. Qxf4 Qxd5 3. Ne5 Kh8 4. Qg5 Qg8 5. Nf7+ Kh7 $10)
2. ... e5
3. dxe6
({5:Mat03} 3. dxe6 Qd4 4. Qxd4 Bxf1 5. Qh8# $18)
({5:-2.62} 3. Re1 Qd6 4. Qc2 Kh7 5. Nxe5+ Kxh6 $19)